If it's not what You are looking for type in the equation solver your own equation and let us solve it.
245n^2-125=0
a = 245; b = 0; c = -125;
Δ = b2-4ac
Δ = 02-4·245·(-125)
Δ = 122500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{122500}=350$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-350}{2*245}=\frac{-350}{490} =-5/7 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+350}{2*245}=\frac{350}{490} =5/7 $
| 9(x+3)-35=40-3x | | 132x+270x=1,201.98 | | -196=14b | | 65=5a | | -16n=-256 | | 3a+2=2a-5 | | 8x-2+2(4x+2)=-2(x+6 | | 4+(3x-1)/2=9 | | (2x+5)+(3+2Y)=0 | | 125h=h+6 | | (2x+3)(3x+2Y)=0 | | 16=v-17 | | 0.2x+10=1.2x+14 | | 6(y-4)-9=-21(-2y+9)=7y | | 2/7x+6=8 | | 18=q(q^2-8q+22) | | -16=b×18 | | 9+3x-x=11 | | 26=9+n | | 8k(k+2)=2k-3 | | -16=b÷18 | | 11=x-3x+9 | | 157x=-3 | | -3(5y+8)-6y=3(y-6)-4 | | 63=-3(3p-3) | | 20x+3=-27 | | 8-5(v-5)=36-4v | | 8n-2(-1-4n)=-62 | | -9(3x-9)+5x=433 | | (16x+3)/(12x+2)=0 | | -3(4y-8)=12 | | -1+2(t+3)=5-(t-3) |